Please find the area bounded by the curves y^2+x=4 and y=x^3. (Please set up the integral and sketch the graph, labeling intersections. You may use NINT to compute.)
The first thing you should do is to solve for a variable. This case you use y. The solved equations are:
The first thing you should do is to solve for a variable. This case you use y. The solved equations are:
Then you would graph the two curves and find the intersects (the bounds).
To find the area of this area, you have to subtract the left curve from the right curve instead of the bottom curve from the top curve. The integral should look like this:
You then can type (4-y^2)-(cube root y),y,-2.307,1.188 into NINT to get the area under the curve.